And if you have all those three things together, then the electric flux has an equation. And this angle here is measured between the electric fields which is the blue lines and the normal or the perpendicular vector of that surface. And so since the normal is the perpendicular of that surface, then the electric flux is gonna be dependent on the angle that the electric field makes with that surface. And the way I like to think about the normal is if my hand, the back of my hand was a surface, then there is a vector that points directly perpendicular to that surface that's called the normal. Now, the way way we measure this angle is we say the electric field lines make some angle with something called the normal of the surface. So clearly what we've seen in these three examples is that the electric flux depends on the angle of the surface. So it's some partial amount of electric flux. And so in this case, the electric field line isn't an all or nothing, it's actually just some. And then some of them are passing through. So some of the field lines are actually passing over it and under it. And then in this situation, we have somewhere in the middle. Remember that the electric field that passes through the surface is defined as the electric flux. So that means that the electric flux at this point is none or is nothing, there is no electric flux because there's nothing actually passing through the surface. So imagine you were to turn that ring and instead of it being upright, you were to turn it on its side, no field lines would actually go through that ring that would kind of just go right over it or underneath it. ![]() Whereas in this situation, now we're gonna have the ring, but instead of it being upright and all the field lines passing through it, what happens is that these electric field lines will pass directly over it. So that means the electric flux is going to be all or maximum or something like that. And in this case, we can say that this ring has sort of like caught all of these electric field lines. Well, in this situation, basically the flux is how much of these lines will pass through the surface. So we've got these couple of examples right here, imagine these blue lines represent the electric field and this represents just a surface kind of like a ring I was just talking about. So when we talk about electric flux, we're gonna be talking about the electric field and specifically how much of this electric field will pass through a surface. The way I like to think about this is kind of like if this field here was like a river and you were to stick like a ring inside of it, how much water passes through the ring? That's sort of how I like to think about flux. So basically, the flux of anything flux is just a measure of how much of something passes through a surface. You'll definitely need it to solve problems, especially when we start talking about Gauss's law. It's a concept that is very important in electrostatics. So for this video, I wanna talk about electric flux. A cube whose sides are of length d is placed in a uniform electric field of magnitude \(\displaystyle E=4.Hey guys. What is the net charge enclosed by the surface?ģ8. The electric flux through a spherical surface is \(\displaystyle 4.0×10^4N⋅m^2/C\). What is the total charge enclosed by the box?ģ7. The electric flux through a cubical box 8.0 cm on a side is \(\displaystyle 1.2×10^3N⋅m^2/C\). Find the magnitude of the electric flux through the shaded face due to q. A charge q is placed at one of the corners of a cube of side a, as shown below. (b) How precisely can we determine the location of the charge from this information?ģ5. (a) How much charge is inside the sphere? ![]() A net flux of \(\displaystyle 1.0×10^4N⋅^m2/C\) passes inward through the surface of a sphere of radius 5 cm. Find the net electric flux though the surfaces of the cube.ģ4. A point charge of \(\displaystyle 10μC\) is at an unspecified location inside a cube of side 2 cm. If there are no other charges in this system, what is the electric flux through one face of the cube?ģ3. A point charge q is located at the center of a cube whose sides are of length a. Find the electric flux through the closed surface whose cross-sections are shown below.ģ2. Determine the electric flux through each closed surface whose cross-section inside the surface is shown below.ģ1. What is the flux through the surface due to the electric field of the charged wire?ģ0. An infinite charged wire with charge per unit length \(\displaystyle λ\) lies along the central axis of a cylindrical surface of radius r and length l. Repeat the previous problem, given that the circular area is (a) in the yz-plane and (b) 45° above the xy-plane.Ģ9. What is its electric flux through a circular area of radius 2.0 m that lies in the xy-plane?Ģ8.
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